IPv4 Questions
Here you will find answers to IPv4 Questions
Question 1
Which statement describes the recommended deployment of IPv4 addressing in the Cisco Enterprise Architecture model?
A. private addressing throughout with public addressing in the Internet Connectivity module
B. private addressing throughout with public addressing in the Internet Connectivity and E-Commerce modules
C. private addressing throughout with public addressing in the Internet Connectivity, E-Commerce, and Remove Access (VPN) modules
D. private addressing throughout with public addressing in the Internet Connectivity,E-Commerce, and Enterprise Branch modules
Answer: C
Question 2
Which route address is the best summary of these network addresses?
A. 192.128.0.0/24
B. 192.128.171.128/3
C. 192.128.168.0/21
D. 192.128.175.0/3
E. 192.128.0.0/16
Answer: C
Question 3
An internal network has servers with private IPv4 addresses that must be visible from the public network. Which kind of address translation should be used to ensure this?
A. many-to-one translation (PAT)
B. many-to-one translation (Dynamic NAT)
C. one-to-one translation (Static NAT)
D. one-to-one translation (NAT Traversal)
Answer: C
Question 4
You are designing IPv6 into an existing IPv4 network. Which strategy can you use to allow both address schemes to coexist, thus facilitating migration?
A. bridge between the two networks
B. deploy stateful address assignments
C. run both the IPv6 and IPv4 stacks on devices
D. redistribute between IPv6-capable and non-IPv6-capable routing protocols
E. enable anycast capability in the routing protocol
Answer: C
Question 5
You are designing IPv6 into an existing IPv4 network. Which two strategies can you use to allow both address schemes to coexist, thus facilitating migration? (Choose two)
A. translate one protocol into the other
B. redistribute between IPv6-capable and non-IPv6-capable routing protocols
C. encapsulate IPv6 packets within IPv4 packets
D. bridge between the IPv6 and IPv4 networks
E. enable anycast capability in the routing protocol
Answer: A C
Question # 2 only provides the answer options. It needs the question part which would what summarizes the following subnets?
192.168.16.0
192.168.17.0
192.168.18.0
192.168.19.0
192.168.20.0
192.168.21.0
192.168.22.0
192.168.23.0
Answer C becomes the correct answer because the CIDR of /21 represents the first 21 bits of each IP subnet being identical.
@Dan, I have no idea how you get to that conclusion.
Your provided list isn’t even in the same range: “192.168.x.x” compared to “192.128.x.x”
yea should be 192.128.16.0 /24 to 192.128.23.0 /24
Correction for Dan’s, there are dumps that sort of follow his thought but Question 2 should be in the form of:
Your subject is to design a medium-sized enterprise’s network with the following network addresses:
192.128.168.0
192.128.169.0
192.128.170.0
192.128.171.0
192.128.172.0
192.128.173.0
192.128.174.0
192.128.175.0
Thus having C as the correct response “192.128.168.0/21”
Several dumps have the same error of “192.168.x.x” instead of “192.128.x.x”
This was the only question that I got wrong due to not picking up an error in the question.
The networks were as follows:
192.168.168.0
192.168.169.0
192.168.170.0
192.168.171.0
192.168.172.0
192.168.173.0
192.168.173.0
192.168.174.0
192.168.175.0
Then the choice of answers were all starting with 192.128.*.*.
Because the 173.0 network is listed twice and I didn’t notice, I just counted the number of networks, which is 9 and is not covered by a /21. Thought they may have changed the question.
So keep an eye out for this error.
C. 192.128.168.0/21 is CORRECT people, do some sumarization calculation and stop winning..!
Thank you guys!
Am I missing something? Answer C (192.128.168.0/21) does not summarize answer A (192.128.0.0/24).
Please explain?
Agree with Certa Cito – Is the answer A?
Sorry … Agree with Certa Cito – Is the answer E?
guys, this is an answer for the last 3 comments:
192.128.0.0/24 summarize the following IPs:
192.128.0.0
192.128.0.1
192.128.0.2
192.128.0.3
192.128.0.4
…
We want to summarize:
192.168.16.0
192.168.17.0
192.168.18.0
192.168.19.0
or
192.128.168.0
192.128.169.0
192.128.170.0
192.128.171.0
or whatever, so, we are talking about the third octect and the last 3 bits of this octect.
the correct answer is always the /21 option, doesn’t matter 192.168.x.x, 192.128.x.x, x.x.16.x, x.x168.x ….